What Is The Radius Of A Circle Whose Equation Is X2 + Y2 + 8X – 6Y + 21 = 0?

What is the radius of a circle whose equation is x2 y2?, The center-radius form of the circle equationis in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being “r”. Therefore the radius of the circle with the given equation would be √9 or 3, first option. Hope this answers the question.

Furthermore, What is the radius of a circle whose equation is?, A circle is a set of points equidistant from a center point. … A common form to write the equation of a circle in is the center-radius form. The center-radius form is: (x−h)2+(y−k)2=r2 Here, the center point is denoted by (h,k) and r is the radius of the circle.

Finally,  What is the center of a circle whose equation is x2 y2 4x 8y 11 0?, Answer: The center of the circle is (-2,4).

Frequently Asked Question:

Which equation represents a circle with the same radius as the circle shown but with a center at (- 1 1?

(x – h)² + (y – k)² = r²

The (h,k) are co-ordinate of your centre of circle, which in this case is (-1,1) and r is the radius of circle.

Which equation represents a circle with the same?

The general equation for a circle is (x−a)2+(y−b)2=r2 Where the center of the circle is at (a,b), and the circle is all the points (x,y) that are r units away from the center (a,b). Let’s figure out how to derive this! Let (x,y) be a point in the coordinate plane.

Which equation represents a circle that contains the Point 2 8 and has a center at 4 0 )?

Which equation represents a circle that contains the point (–2, 8) and has a center at (4, 0)? Distance formula: StartRoot (x 2 minus x 1) squared + (y 2 minus y 1) squared EndRoot (x – 4)2 + y2 = 100 (x – 4)2 + y2 = 10 x2 + (y – 4)² = 10 x2 + (y – 4)² = 100.

Which equation represents a circle that contains the point (- 5 3 and has a center at (- 2 1?

Which equation represents a circle that contains the point (-5, –3) and has a center at (-2, 1)? Distance formula: (x2 – xy)2 + (V2 – 71)2. OOOO. (x – 1)2 + (y + 2)2 = 25.

What is the center of a circle whose equation is?

A common form to write the equation of a circle in is the center-radius form. The center-radius form is: (x−h)2+(y−k)2=r2 Here, the center point is denoted by (h,k) and r is the radius of the circle.

How do you find the radius of a circle whose equation is in the form x2 y2 Z?

Which explains how to find the radius of a circle whose equation is in the form x2 + y2 = z? The radius is the square root of the constant term, z.

Which equation represents a circle that contains the Point 2 8 and has a center at 4 0 )?

Which equation represents a circle that contains the point (–2, 8) and has a center at (4, 0)? Distance formula: StartRoot (x 2 minus x 1) squared + (y 2 minus y 1) squared EndRoot (x – 4)2 + y2 = 100 (x – 4)2 + y2 = 10 x2 + (y – 4)² = 10 x2 + (y – 4)² = 100.

How do you find the center and radius of a circle from an equation?

  1. x 2 + y 2 + 2 g x + 2 f y + c = 0 is used to work out the centre of the circle, and the radius.
  2. ( x − a ) 2 + ( y − b ) 2 = r 2 is used to write the equation of the circle when you know the centre and the radius.

Which explains how do you find the radius of a circle whose equation is in the form x2 y2 Z?

Which explains how to find the radius of a circle whose equation is in the form x2 + y2 = z? The radius is the square root of the constant term, z.

What are the center and radius of the circle whose equation is − 5 )! 3 )! 2?

1 Answer. Answer is (2) i.e. center is (−5,3) and radius is 9 .

How do you use Radius formula?

Just remember to divide the diameter by two to get the radius. If you were asked to find the radius instead of the diameter, you would simply divide 7 feet by 2 because the radius is one-half the measure of the diameter. The radius of the circle is 3.5 feet. You can also use the circumference and radius equation.

What is the radius of the circle whose equation is x2 y2 8?

Therefore, radius of the circle is √8.

What is the radius of a circle whose equation is?

A circle is a set of points equidistant from a center point. … A common form to write the equation of a circle in is the center-radius form. The center-radius form is: (x−h)2+(y−k)2=r2 Here, the center point is denoted by (h,k) and r is the radius of the circle.

What is the radius of the circle whose equation is x2 y2 9?

The center-radius form of the circle equationis in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being “r”. Therefore the radius of the circle with the given equation would be √9 or 3, first option.

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