What is the general form of the equation for the given circle centered at 0?, Since standard equation of a circle is x² + y² = r² with origin(0, 0) as center.
Furthermore, What is the general form of the equation for the given circle Brainly?, Answer Expert Verified
The equation of a circle is (x – xo)^2 + (y – yo)^2 = r^2, where (xo,yo) is the center of the circle and r is the radius of the circle.
Finally, What is the general form of the equation of the given circle?, The graph of a circle is completely determined by its center and radius. Standard form for the equation of a circle is (x−h)2+(y−k)2=r2. The center is (h,k) and the radius measures r units.
Frequently Asked Question:
What is the general form of the equation of the given circle with center a (- 3 12?
Answer Expert Verified
x² + 6x + y² – 24y + 128 = 0 is your equation.
What is the general form of the equation of a circle with center at a B and radius of length M?
SOLUTION: What is the general form of the equation of a circle with center at (a,b) and radius of length m? A.x^2+y^2-2ax-2by+(a^2+b^2-m^2)=0 B.x^2+y^2+2ax+2by+(a^2+b^2-m^2)=0 C.x^2+y^2- Question 886968: What is the general form of the equation of a circle with center at (a,b) and radius of length m?
What is the general form of the equation of the given circle with the center a?
Now, that we have circle A’s new center and radius, we can write its general equation using (x – h)2 + (y – k)2 = r2. (x – (–2))2 + (y – 2)2 = (2√29)2 = 22(√29)2 = 4(29) = 116. (x + 2)2 + (y – 2)2 = 116. The answer is (x + 2)2 + (y – 2)2 = 116.
How do you find the general equation of a circle?
We know that the general equation for a circle is ( x – h )^2 + ( y – k )^2 = r^2, where ( h, k ) is the center and r is the radius. So add 21 to both sides to get the constant term to the righthand side of the equation. Then complete the square for the y terms.
What is the standard form of the equation of a circle with center 3 − 2 and radius 4?
This is the equation of our given circle, in standard form. Summarizing: The equation of the circle with center (−3,−4) and radius 3,in standard form, is: (x+3)2+(y+4)2 = 9.
What is the general form of a circle equation?
2) The general form : x2 + y2 + Dx + Ey + F = 0, where D, E, F are constants. If the equation of a circle is in the standard form, we can easily identify the center of the circle, (h, k), and the radius, r . Note: The radius, r, is always positive.
What is the general form of the equation of the given circle with center?
Explanation: The general equation of a circle is (x – h)2 + (y – k)2 = r2, where (h, k) represents the location of the circle’s center, and r represents the length of its radius. Circle A first has the equation of (x – 4)2 + (y + 3)2 = 29. This means that its center must be located at (4, –3), and its radius is √29.
What is the general form of the equation of the given circle with center a (- 3 12?
Answer Expert Verified
x² + 6x + y² – 24y + 128 = 0 is your equation.
What is the general form?
The formula 0 = Ax + By + C is said to be the ‘general form‘ for the equation of a line. … Once these are given, the values for x and y that make the statement true express a set, or locus, of (x, y) points which form a certain line.
What is the general form of the equation of the given circle?
The graph of a circle is completely determined by its center and radius. Standard form for the equation of a circle is (x−h)2+(y−k)2=r2. The center is (h,k) and the radius measures r units.
What is the general form of the equation of the given circle with center a (- 3 12?
Answer Expert Verified
x² + 6x + y² – 24y + 128 = 0 is your equation.
What is the general form of the equation of a circle with center at a B and radius of length M?
SOLUTION: What is the general form of the equation of a circle with center at (a,b) and radius of length m? A.x^2+y^2-2ax-2by+(a^2+b^2-m^2)=0 B.x^2+y^2+2ax+2by+(a^2+b^2-m^2)=0 C.x^2+y^2- Question 886968: What is the general form of the equation of a circle with center at (a,b) and radius of length m?
What is the general form of the equation for the given circle centered at?
The general equation for a circle is (x – h)² + (y – k)² = r², where (h, k) represents the center of the circle, r is the radius, and x and y form the coordinates of all the points on the circle’s perimeter.
What is the general form of the equation of the given circle with center a (- 3 12?
Answer Expert Verified
x² + 6x + y² – 24y + 128 = 0 is your equation.
What is the general form of the equation of the given circle with the center a?
Now, that we have circle A’s new center and radius, we can write its general equation using (x – h)2 + (y – k)2 = r2. (x – (–2))2 + (y – 2)2 = (2√29)2 = 22(√29)2 = 4(29) = 116. (x + 2)2 + (y – 2)2 = 116. The answer is (x + 2)2 + (y – 2)2 = 116.
How do you find the general equation of a circle?
We know that the general equation for a circle is ( x – h )^2 + ( y – k )^2 = r^2, where ( h, k ) is the center and r is the radius. So add 21 to both sides to get the constant term to the righthand side of the equation. Then complete the square for the y terms.
What is the standard form of the equation of a circle with center 3 − 2 and radius 4?
This is the equation of our given circle, in standard form. Summarizing: The equation of the circle with center (−3,−4) and radius 3,in standard form, is: (x+3)2+(y+4)2 = 9.