What is the equation of a circle whose center is at the origin and whose radius is 16? x2 + y2 = 4 x2 + y2 = 16 x2 + y2 = 256.Feb 13, 2017
Which of the following is the equation of a circle whose center is at the origin and whose radius is 4?, The standard form: (x – h)^2 + (y-k)^2 = r^2, where (h, k) is the center and r is the radius of the circle. Given: (h, k) = (0, 0) and r = 4. Hope this will helpful. Thank you.
Furthermore, How would you write the equation of a circle given its radius and its center at the origin What about if the center is at H k )?, The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.
Finally, What is the equation of a unit circle centered in the origin?, The unit circle is a circle centered at the origin, with a radius of one. The equation of the unit circle is u2 + v2 = 1.
Frequently Asked Question:
What is the radius of a circle whose center is the origin and that passes through the point 5 12?
1 Answer. David G. The radius is simply the distance from the center to the edge, and we can use Pythagoras’ Theorem to calculate that for this circle the radius is 13 units.
How do you find the radius of a circle with the center?
The center–radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being “r”.
What is the equation of a circle with center at the origin and whose radius is 1?
The equation of a circle written in the form (x−h)2+(y−k)2=r2 where (h,k) is the center and r is the radius. The circle centered at the origin with radius 1; its equation is x2+y2=1.
What is the center at the origin of a circle?
Thus, using the theorem of Pythagoras, x2 + y2 = r2 , and this is the equation of a circle of radius r whose centre is the origin O(0, 0). The equation of a circle of radius r and centre the origin is x2 + y2 = r2 .
What is the equation of a circle centered at the origin?
The equation of a circle with center (h,k) and radius r is given by (x−h)2+(y−k)2=r2 . For a circle centered at the origin, this becomes the more familiar equation x2+y2=r2 .
What is the equation of a circle with center at the origin and whose radius is 1?
The equation of a circle written in the form (x−h)2+(y−k)2=r2 where (h,k) is the center and r is the radius. The circle centered at the origin with radius 1; its equation is x2+y2=1.
What is the equation of a center circle?
The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. If a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.
What is the standard form of the equation of the circle with center at the origin and radius 2?
2 Answers By Expert Tutors
The standard form for the equation of a circle with radius r , center at (h, k) is given as (x – h)2 + (y – k)2 = r2. Since the origin is given as the center, h and k are both equal to zero.
Which of the following is the equation of a circle whose center is at the origin and whose radius is four?
The standard form: (x – h)^2 + (y-k)^2 = r^2, where (h, k) is the center and r is the radius of the circle. Given: (h, k) = (0, 0) and r = 4. Hope this will helpful. Thank you.
What is the equation of a circle with the center at the origin?
The equation of a circle with center (h,k) and radius r is given by (x−h)2+(y−k)2=r2 . For a circle centered at the origin, this becomes the more familiar equation x2+y2=r2 .
What is the equation of a circle whose center is at the origin and whose radius is 16?
What is the equation of a circle whose center is at the origin and whose radius is 16? x2 + y2 = 4 x2 + y2 = 16 x2 + y2 = 256.
What is the equation of the circle whose Centre is the origin and radius A units *?
The equation of a circle with centre at (h, k) and radius equal to a, is (x – h)2 + (y – k)2 = a2. When the centre of the circle coincides with the origin i.e., h = k = 0.
What is the equation of the circle if the center is at the origin?
x2 + y2 = r2 , and this is the equation of a circle of radius r whose centre is the origin O(0, 0). The equation of a circle of radius r and centre the origin is x2 + y2 = r2 . What is the equation of a circle of radius r, centred at the point C(a, b)?
How do you write the equation of a circle given its radius and its center at the origin What about if the center is at H k )?
The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.
Which is the standard equation for a circle centered at the origin with radius?
Vocabulary Language: English ▼ English
| Term | Definition |
| Equation of a Circle | If the center of a circle is (0, 0), then the equation of the circle is of the form x^2+y^2=r^2, where r is the radius. |
| Radius | The radius of a circle is the distance from the center of the circle to the edge of the circle. |
Which of the following is the equation of a circle whose center is at the origin and whose radius is 4?
The standard form: (x – h)^2 + (y-k)^2 = r^2, where (h, k) is the center and r is the radius of the circle. Given: (h, k) = (0, 0) and r = 4. Hope this will helpful. Thank you.
How do you write the equation of a circle given its radius and its center at the origin What about if the center is at H K?
The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.