What is the 22nd term of the arithmetic sequence where a1 8 and a9 56 134 142 150 158?, The 22nd term of the arithmetic sequence is 134.
Furthermore, What is the 24th term of the arithmetic sequence where a1 8 and a9 56 134 140 146 152?, 1 Answer. Thus, the 24th term is 146 .
Finally, What is the 6th term of the geometric sequence where a1 128 and a3 8?, The 6th term of the sequence is 0.125.
Frequently Asked Question:
What is the common ratio of the geometric sequence 2 8 32?
Explanation: This is a geometric sequence, since each term after the first is obtained by multiplying a common ratio, r . The common ratio is 4 .
What is the common ratio in the geometric sequence?
In mathematics, a geometric progression, also known as a geometric sequence, is a sequence of non-zero numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio.
Which term of the GP 2 8 32 up to n terms is 131072?
Hence, 131072 is the 9th term in the given G.P.
What is the common ratio of the geometric sequence 16 24 36 54?
The common ratio is 1.5 .
How do you find the common ratio of a geometric sequence of fractions?
Write down any two sequential terms of the geometric series, preferably the first two. For example, if your series is 3/2 + -3/4 + 3/8 + -3/16 + .. your can use 3/2 and -3/4. Divide the second term by the first term to find the common ratio.
What is the 6th term of the geometric sequence?
Hence, the 6th term is 6075.
What is the 6th term of the geometric sequence where a1?
Answer: The sixth term of the geometric sequence is 4.
What is the 7th term of the geometric sequence where a1 − 625 and a2 125/1 point?
The 7th term of the geometric sequence where a1 = –625 and a2 = 125 is –125.
What is the 24th term of the arithmetic sequence where a1 8 and a9 56?
1 Answer. Thus, the 24th term is 146 .
What is the 24th term of the sequence?
The 24th term is a24=148.
What is the 23rd term of the arithmetic sequence where a1 8 and a9 48?
Answer: 23rd term of A.P is 118. Step-by-step explanation: Given that the first and ninth term of the arithmetic sequence which is 8 and 48 respectively.
What is the 22nd term of the arithmetic sequence where a1 8 and a9 56 134 142 150 158?
The 22nd term of the arithmetic sequence is 134.
What is the 22nd term of the arithmetic sequence where a1 8 and a9 56 6 points?
The 22nd term of the arithmetic sequence is 134.
What is the 22nd term of the arithmetic sequence?
Answer:the 22nd term is 117. The formula for determining the nth term of an arithmetic sequence is expressed as. Tn = a + (n – 1)d. Where. a represents the first term of the sequence.
What is the 23rd term of the arithmetic sequence where a1 8 and a9 48?
Answer: 23rd term of A.P is 118. Step-by-step explanation: Given that the first and ninth term of the arithmetic sequence which is 8 and 48 respectively.
What is the 23rd term of the arithmetic sequence when a1 8?
Therefore 23rd term of the sequence is 118.
What is the 24th term of the arithmetic sequence where a1 8 and a9 56 6 points?
1 Answer. Thus, the 24th term is 146 .