What is the probability that a 5-card poker hand has at least three spades?, The probability of hand will contain 3 spades and 2 hearts if 5 cards are dealt from 52 playing cards = (13C3 × 13C2)/52C5. (286 × 78)/2,598,960 = 0.0085. The probability of hand will contain 3 spades and 2 hearts if 5 cards are dealt from 52 playing cards = 0.0085.
Furthermore, How many 5-card poker hands contain at least one card in each suit?, Finally for each of these choices, there are 36 possible cards for the fifth card. So the answer would be 4!
Finally, What is the probability that a 5-card poker hand has at least one ace?, This probability is (485)(525), for we have 48 choose 5 possible hands with no aces. Then the solution to the problem – that is, the probability of at least one ace appearing in a 5–card hand – is one minus the complement: 1−(485)(525).
Frequently Asked Question:
How many 5 cards selection that contain at least one club?
According to Wolfram|Alpha is equal to 2,023,203 possible hands involving at least one club. Also rather than calculating this directly as above we can see that since there are (395) ways of choosing a hand not involving a club then there must be (525)−(395) ways of choosing a hand that has at least one club.
How many 5-card poker hands contain at least one card in each suit?
Finally for each of these choices, there are 36 possible cards for the fifth card. So the answer would be 4!
How many 5-card hands have at least two cards with the same rank?
A 5–card hand is drawn from a deck of standard playing cards. (a) How many 5–card hands have at least one club? (b) How many 5–card hands have at least two cards with the same rank? There are (52 choose 5) total ways to pick each possible hand.
How many ways can you choose the 5 cards?
= 2598960 different ways to choose 5 cards from the available 52 cards.
How many different 5-card hands are there?
Probability of Two Pair
First, count the number of five-card hands that can be dealt from a standard deck of 52 cards. We did this previously, and found that there are 2,598,960 distinct poker hands. Next, count the number of ways that five cards can be dealt to produce two pair.
What is the probability that you have at least one ace?
When randomly selecting 2 cards from a deck, there is a roughly chance you will draw at least one ace, or 3 hands in 20, or approximately 1 in 6.67 two-card hands.
How many 5 card hands have at least one queen?
The total of these is 108,336 – that’s the correct answer. You also could have done this: There are 4C0 * 48C5 = 1,712,304 hands with no queens. There are 4C1 * 48C4 = 778,320 hands with exactly one queen.
What is the probability that a 5 card poker hand has at least three spades?
The probability of hand will contain 3 spades and 2 hearts if 5 cards are dealt from 52 playing cards = (13C3 × 13C2)/52C5. (286 × 78)/2,598,960 = 0.0085. The probability of hand will contain 3 spades and 2 hearts if 5 cards are dealt from 52 playing cards = 0.0085.
How many hands have at least one ace?
Likewise, there are 48 previously uncounted hands with H, 48 with C, and 48 with D in the R position, for a total of 4 48 = 192 additional legal hands. Thus, there are a grand total of 396 ordered hands that contain at least one ace. Of these hands, exactly 12 have aces in both the L and R positions.
How many 5 card hands contain cards of exactly one suit?
=111540 ways. =5148 ways. How many 5 – card hands drawn from a standard deck of 52 cards (2 colors, 4 suits, 13 different cards for each suit) have all five cards being the same color? There are 52 cards, 26 red and 26 black.
How many different five-card hands have all five cards of a single suit?
Question 478154: How many five–card hands consist of five cards of the same suit? there are 13 cards in each suit. if the suit is clubs, then the possible number of hands would be 13C5 = 1287. each hand would be different from the other hand, but each hand would contain all clubs.
How many hands have at least one card from each suit?
For a five-card hand to have one card in each suit, it must be the case that the hand contains two cards from one of the suits and one card from each of the others. For the suit with two cards, there are ways of choosing those two cards.
How many 5 cards selection that contain at least one club?
According to Wolfram|Alpha is equal to 2,023,203 possible hands involving at least one club. Also rather than calculating this directly as above we can see that since there are (395) ways of choosing a hand not involving a club then there must be (525)−(395) ways of choosing a hand that has at least one club.
What is the probability that a 5-card poker hand has at least Threespades?
The probability of hand will contain 3 spades and 2 hearts if 5 cards are dealt from 52 playing cards = (13C3 × 13C2)/52C5. (286 × 78)/2,598,960 = 0.0085. The probability of hand will contain 3 spades and 2 hearts if 5 cards are dealt from 52 playing cards = 0.0085.
How many five-card poker hands containing three of a kind are possible?
| hand | number | Probability |
| 3-of-a-kind | 54,912 | .0211 |
| two pairs | 123,552 | .0475 |
| pair | 1,098,240 | .4226 |
| high card | 1,302,540 | .5012 |
How do you find the probability of 5-card poker hands?
| Hand | Probability | Number of Hands |
| Full House | 0.00144058 | 3744 |
| Four of a Kind | 0.000240096 | 624 |
How many 5-card hands contain all clubs?
if the suit is clubs, then the possible number of hands would be 13C5 = 1287. each hand would be different from the other hand, but each hand would contain all clubs. there are 4 suits in the deck so the total number would be 4 times that. the total would be equal to 5148.