The current I through the resistor immediately after the switch is moved to position b is 180 mA. The charge Q on the capacitor at t=50 μs is 1.1 × 10–5 C.
What is the current through the 20ω resistor immediately after the switch is closed?, The current through the 20Ω resistor after the switch has been closed a long time is zero. The energy stored in the inductor after a long time is zero. The potential difference across the 20Ω is, therefore, zero.
Furthermore, What is the charge q on the capacitor immediately after the switch is close?, Before the switch is closed, the charge Q on the capacitor is zero and the voltage across the capacitor = V = Q/C = 0. Right after the switch is closed, the charge has not had time to build up on the capacitor and the charge and voltage are still zero.
Finally, What is the charge q on the capacitor at t 50μs T 50 μ s?, The charge Q on the capacitor at t = 50 µs is 10.92 µC.
Frequently Asked Question:
What is the current I through the resistor at T 200μst 200μs?
The charge Q on the capacitor at t = 200µs is 2.44 µC. B. The current I through the resistor at t = 200 µs is 0.0244A.
What is the charge q on the capacitor immediately after the switch is moved to position B?
The charge on the capacitor immediately after the switch is moved to position b is 1.8 × 10–5 C. The current I through the resistor immediately after the switch is moved to position b is 180 mA. The charge Q on the capacitor at t=50 μs is 1.1 × 10–5 C.
What is the charge q on the capacitor at t 200μs?
The charge Q on the capacitor at t = 200µs is 2.44 µC.
What is the charge q on the capacitor?
The charge Q on the plates is proportional to the potential difference V across the two plates. The capacitance C is the proportional constant, Q = CV, C = Q/V.
What is the charge on the capacitor after the switch has been closed for a long time answer in units of C?
Thus, the charge on the capacitor after the switch has been closed for a very long time is 770.35 μC 770.35 μ C .
What is E in capacitor charging equation?
(Note that in the two parts of the figure, the capital script E stands for emf, q stands for the charge stored on the capacitor, and τ is the RC time constant. ) In terms of voltage, across the capacitor voltage is given by Vc=Q/C, where Q is the amount of charge stored on each plate and C is the capacitance.
What is the current I through the resistor at T 200μs?
The charge Q on the capacitor at t=200 μs is 1.1 × 10–5 C. The current I through the resistor at t=200 μs is 24 mA.
What is the current II through the resistor at T 50μs T 50 μ s?
The current I through the resistor at t = 50 µs is 0.109A.
What will be the charge on the capacitor a long time after the switch is moved to position 2?
fully charged
What is the charge q on the capacitor at t 50?
The charge Q on the capacitor at t = 50 µs is 10.92 µC.
What happens to the charge on the capacitor immediately after the switch is thrown?
As soon as the switch is closed, the charge on the capacitor increases but the voltage across it decreases as a function of time.
How do you find the charge Q of a capacitor?
The amount of charge that moves into the plates depends upon the capacitance and the applied voltage according to the formula Q=CV, where Q is the charge in Coulombs, C is the capacitance in Farads, and V is the potential difference between the plates in volts.
What is Q for a capacitor?
The Q factor of a capacitor, also known as the quality factor, or simply Q, represents the efficiency of a given capacitor in terms of energy losses.
What is the charge on the capacitor?
Capacitors do not store charge. Capacitors actually store an imbalance of charge. If one plate of a capacitor has 1 coulomb of charge stored on it, the other plate will have −1 coulomb, making the total charge (added up across both plates) zero.
What is the value of Q in capacitance?
The voltage is V = Ed = σd/ε0. The charge is Q = σA. Therefore Q/V = σAε0/σd = Aε0/d.) The SI unit of capacitance is Coulomb/Volt = Farad (F).
…
Capacitance.
| Material | Dielectric Constant |
|---|---|
| Water (distilled) | 76.7 to 78.2 |
| Wood | 1.2 to 2.1 |
What happens to capacitor when switch is closed for a long time?
When the switch is first closed, the voltage across the capacitor (which we were told was fully discharged) is zero volts; thus, it first behaves as though it were a short-circuit. Over time, the capacitor voltage will rise to equal battery voltage, ending in a condition where the capacitor behaves as an open-circuit.